a function that takes 3 command-line arguments

new4c · #1 01-06-2008, 01:33 AM

I really need help on this one. Can't believe getting this kind of question as a newbie to C programming. Thanks alot
Write a program that takes 3 command-line arguments – the first is a flag, then second is a character, the third is a filename. If the flag argument is ‘s’ then it prints only those lines in the file that contain the character. If the flag argument is ‘-n’ then it prints only those lines in the file that do *not* contain the character.

Mahesh.Shetye · #2 03-22-2008, 03:02 PM

Quote:

Originally Posted by new4c

I really need help on this one. Can't believe getting this kind of question as a newbie to C programming. Thanks alot
Write a program that takes 3 command-line arguments – the first is a flag, then second is a character, the third is a filename. If the flag argument is ‘s’ then it prints only those lines in the file that contain the character. If the flag argument is ‘-n’ then it prints only those lines in the file that do *not* contain the character.

you shud use main(int argc, char* argv[]) function insted of main() function in your program.

wesley001 · #3 06-28-2008, 01:53 AM

and for more control about argument handling you can use getopt (from GNU).
and else like Mahesh.Shetye said:

Code:

#include <stdio.h>

int main(int argc, char *argv[])
{
if(argc!=4){
printf("Usage: %s <flag> <char> <file>",argv[0])
return 0;
}
// remaining code here
return 0;
}

heavensgate15 · #4 12-29-2008, 01:14 AM

wow... nose bleed....